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Recent Questions
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Not quite. In a formal form, without using logical krakozyabras, your reasoning can be expressed as follows (x – clean, y-dirty, x1-remains clean under dirt, x2 – cannot become dirty without being clean):
not all x's are y's
all y's are x1 and all y's are x2; hence, all y's are x
To make this argument logically valid and correct, we can add the axiom “if all y are x1 and all y are x2, then all y are x”.